nateraw
/
gairmath-abel-7b
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- 32 runs
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L40S
Prediction
nateraw/gairmath-abel-7b:08026755IDyav75qlbw6matrhjoejbyg65oiStatusSucceededSourceWebHardwareA40 (Large)Total durationCreatedInput
- top_k
- 50
- top_p
- 0.95
- message
- Question: Farmer Brown has 60 animals on his farm, all either chickens or cows. He has twice as many chickens as cows. How many legs do the animals have, all together? Answer: Let's think step by step.
- temperature
- 0.8
- max_new_tokens
- 1024
Output
1. The problem states that Farmer Brown has 60 animals on his farm, all either chickens or cows. He has twice as many chickens as cows. We need to find out how many legs the animals have in total. 2. Let's assume the number of cows is x. Since Farmer Brown has twice as many chickens as cows, the number of chickens is 2x. 3. The total number of animals is 60, so we can write the equation x + 2x = 60. 4. Simplifying this equation, we get 3x = 60. 5. Dividing both sides by 3, we find x = 20. 6. Therefore, the number of cows is 20. 7. Since each cow has 4 legs and each chicken has 2 legs, the total number of legs is 4 * 20 + 2 * 60 = 80 + 120 = 200. 8. [Final solution] Thus, the animals have a total of 200 legs. #### 200Generated in
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