peter65374/openbuddy-mistral-7b | Run with an API on Replicate

peter65374 / openbuddy-mistral-7b

Openbuddy finetuned mistral-7b in GPTQ quantization in 4bits by TheBloke

Cold

Public
69 runs
L40S
GitHub
License

Iterate in playground

Run with an API

Playground API Examples README Versions

Input

prompt

*string

Shift + Return to add a new line

Problem statement: """一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？"""

Correct solution: """我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。

先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。

先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。

所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。""

Student’s solution: """(4/10)*(6/9) = 24/90 = 4/15"""
---
请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.Problem statement: """一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？"""

Correct solution: """我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。

先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。

先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。

所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。""

Student’s solution: """(4/10)*(6/9) = 24/90 = 4/15"""
---
请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.

max_new_tokens

integer

(minimum: 1, maximum: 3500)

The maximum number of tokens the model should generate as output.

Default: 1024

temperature

number

The value used to modulate the next token probabilities.

Default: 0.7

top_p

number

(minimum: 0.01, maximum: 1)

A probability threshold for generating the output. If < 1.0, only keep the top tokens with cumulative probability >= top_p (nucleus filtering). Nucleus filtering is described in Holtzman et al. (http://arxiv.org/abs/1904.09751).

Default: 0.95

top_k

integer

(minimum: 1, maximum: 100)

The number of highest probability tokens to consider for generating the output. If > 0, only keep the top k tokens with highest probability (top-k filtering).

Default: 40

do_sample

boolean

Whether or not to use sampling ; use greedy decoding otherwise.

Default: true

num_beams

integer

(minimum: 1, maximum: 10)

Number of beams for beam search. 1 means no beam search.

Default: 1

repetition_penalty

number

(minimum: 0.01, maximum: 5)

Repetition penalty, (float, *optional*, defaults to 1.0): The parameter for repetition penalty. 1.0 means no penalty. values greater than 1 discourage repetition, less than 1 encourage it. See [this paper](https://arxiv.org/pdf/1909.05858.pdf) for more details.

Default: 1

prompt_template

string

Shift + Return to add a new line

You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.
User: Hi
Assistant: Hello, how can I help you?</s>
User: {prompt}
Assistant:You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.
User: Hi
Assistant: Hello, how can I help you?</s>
User: {prompt}
Assistant:

The template used to format the prompt. The input prompt is inserted into the template using the `{prompt}` placeholder.

Default: "You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.\nUser: Hi\nAssistant: Hello, how can I help you?</s>\nUser: {prompt}\nAssistant:"

padding_mode

boolean

Whether to pad the left side of the prompt with eos token.

Default: true

stop_sequences

string

Shift + Return to add a new line

A comma-separated list of sequences to stop generation at. For example, '<end>,<stop>' will stop generation at the first instance of 'end' or '<stop>'.

debug

boolean

provide debugging output in logs

Default: false

Run this model in Node.js with one line of code:

npx create-replicate --model=peter65374/openbuddy-mistral-7b

or set up a project from scratch

Install Replicate’s Node.js client library:

npm install replicate

Set the REPLICATE_API_TOKEN environment variable:

export REPLICATE_API_TOKEN=<paste-your-token-here>

Find your API token in your account settings.

Import and set up the client:

import Replicate from "replicate";

const replicate = new Replicate({
  auth: process.env.REPLICATE_API_TOKEN,
});

Run peter65374/openbuddy-mistral-7b using Replicate’s API. Check out the model's schema for an overview of inputs and outputs.

const output = await replicate.run(
  "peter65374/openbuddy-mistral-7b:8199f01fa38cf1b42ff59f231f0ed05fc5214fce4065c7ea33d2fadc79d90f11",
  {
    input: {
      debug: true,
      top_k: 40,
      top_p: 0.95,
      prompt: "Problem statement: \"\"\"一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？\"\"\"\n\nCorrect solution: \"\"\"我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。\n\n先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。\n\n先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。\n\n所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。\"\"\n\nStudent’s solution: \"\"\"(4/10)*(6/9) = 24/90 = 4/15\"\"\"\n---\n请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.",
      do_sample: true,
      num_beams: 1,
      temperature: 0.7,
      padding_mode: true,
      max_new_tokens: 1024,
      prompt_template: "You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.\nUser: Hi\nAssistant: Hello, how can I help you?</s>\nUser: {prompt}\nAssistant:",
      repetition_penalty: 1
    }
  }
);

console.log(output);

To learn more, take a look at the guide on getting started with Node.js.

Install Replicate’s Python client library:

pip install replicate

Set the REPLICATE_API_TOKEN environment variable:

export REPLICATE_API_TOKEN=<paste-your-token-here>

Find your API token in your account settings.

Import the client:

import replicate

Run peter65374/openbuddy-mistral-7b using Replicate’s API. Check out the model's schema for an overview of inputs and outputs.

output = replicate.run(
    "peter65374/openbuddy-mistral-7b:8199f01fa38cf1b42ff59f231f0ed05fc5214fce4065c7ea33d2fadc79d90f11",
    input={
        "debug": True,
        "top_k": 40,
        "top_p": 0.95,
        "prompt": "Problem statement: \"\"\"一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？\"\"\"\n\nCorrect solution: \"\"\"我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。\n\n先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。\n\n先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。\n\n所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。\"\"\n\nStudent’s solution: \"\"\"(4/10)*(6/9) = 24/90 = 4/15\"\"\"\n---\n请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.",
        "do_sample": True,
        "num_beams": 1,
        "temperature": 0.7,
        "padding_mode": True,
        "max_new_tokens": 1024,
        "prompt_template": "You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.\nUser: Hi\nAssistant: Hello, how can I help you?</s>\nUser: {prompt}\nAssistant:",
        "repetition_penalty": 1
    }
)

# The peter65374/openbuddy-mistral-7b model can stream output as it's running.
# The predict method returns an iterator, and you can iterate over that output.
for item in output:
    # https://replicate.com/peter65374/openbuddy-mistral-7b/api#output-schema
    print(item, end="")

To learn more, take a look at the guide on getting started with Python.

Set the REPLICATE_API_TOKEN environment variable:

export REPLICATE_API_TOKEN=<paste-your-token-here>

Find your API token in your account settings.

Run peter65374/openbuddy-mistral-7b using Replicate’s API. Check out the model's schema for an overview of inputs and outputs.

curl -s -X POST \
  -H "Authorization: Bearer $REPLICATE_API_TOKEN" \
  -H "Content-Type: application/json" \
  -H "Prefer: wait" \
  -d $'{
    "version": "peter65374/openbuddy-mistral-7b:8199f01fa38cf1b42ff59f231f0ed05fc5214fce4065c7ea33d2fadc79d90f11",
    "input": {
      "debug": true,
      "top_k": 40,
      "top_p": 0.95,
      "prompt": "Problem statement: \\"\\"\\"一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？\\"\\"\\"\\n\\nCorrect solution: \\"\\"\\"我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。\\n\\n先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。\\n\\n先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。\\n\\n所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。\\"\\"\\n\\nStudent’s solution: \\"\\"\\"(4/10)*(6/9) = 24/90 = 4/15\\"\\"\\"\\n---\\n请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.",
      "do_sample": true,
      "num_beams": 1,
      "temperature": 0.7,
      "padding_mode": true,
      "max_new_tokens": 1024,
      "prompt_template": "You are a helpful high school Math tutor. If you don\'t know the answer to a question, please don\'t share false information. You can speak fluently in many languages.\\nUser: Hi\\nAssistant: Hello, how can I help you?</s>\\nUser: {prompt}\\nAssistant:",
      "repetition_penalty": 1
    }
  }' \
  https://api.replicate.com/v1/predictions

To learn more, take a look at Replicate’s HTTP API reference docs.

Output

好的，让我们来看一下这道题。题目要求我们计算一个球是红色，另一个球是蓝色的概率。这个问题可以通过条件概率公式来解决。我们可以先抽出红球，然后再抽出蓝球，也可以先抽出蓝球，然后再抽出红球。所以，我们需要把这两种情况的概率加起来。如果我们先抽出红球，然后再抽出蓝球，那么这两次抽球的概率分别是 (4/10) 和 (6/9)。这时候，我们需要将它们相乘，得到的结果是 (4/10)*(6/9) = 24/90 = 4/15。如果我们先抽出蓝球，然后再抽出红球，那么这两次抽球的概率分别是 (6/10) 和 (4/9)。这时候，我们同样需要将它们相乘，得到的结果是 (6/10)*(4/9) = 24/90 = 4/15。最后，我们将这两种情况的概率相加，得到的结果是 (4/15) + (4/15) = 8/15。所以，一个球是红色，另一个球是蓝色的概率是 8/15。

{
  "completed_at": "2023-10-27T09:14:39.025601Z",
  "created_at": "2023-10-27T09:14:10.926189Z",
  "data_removed": false,
  "error": null,
  "id": "h6frmvlb2xqhjrzqfucgujm73y",
  "input": {
    "debug": true,
    "top_k": 40,
    "top_p": 0.95,
    "prompt": "Problem statement: \"\"\"一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？\"\"\"\n\nCorrect solution: \"\"\"我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。\n\n先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。\n\n先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。\n\n所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。\"\"\n\nStudent’s solution: \"\"\"(4/10)*(6/9) = 24/90 = 4/15\"\"\"\n---\n请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.",
    "do_sample": true,
    "num_beams": 1,
    "temperature": 0.7,
    "padding_mode": true,
    "max_new_tokens": 1024,
    "prompt_template": "You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.\nUser: Hi\nAssistant: Hello, how can I help you?</s>\nUser: {prompt}\nAssistant:",
    "repetition_penalty": 1
  },
  "logs": "Your formatted prompt is:\nYou are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.\nUser: Hi\nAssistant: Hello, how can I help you?</s>\nUser: Problem statement: \"\"\"一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？\"\"\"\nCorrect solution: \"\"\"我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。\n先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。\n先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。\n所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。\"\"\nStudent’s solution: \"\"\"(4/10)*(6/9) = 24/90 = 4/15\"\"\"\n---\n请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.\nAssistant:\nSetting `pad_token_id` to `eos_token_id`:2 for open-end generation.\nafter initialization, first token took 0.108\n好\n的\n，让\n我\n们\n来\n看\n一\n下\n这\n道\n题\n。\n题\n目\n要\n求\n我\n们\n计\n算\n一个\n球\n是\n红\n色\n，另\n一个\n球\n是\n蓝\n色\n的\n概\n率\n。这\n个\n问\n题\n可\n以\n通\n过\n条\n件\n概\n率\n公\n式\n来\n解\n决\n。\n我\n们\n可\n以\n先\n抽\n出\n红\n球\n，然\n后\n再\n抽\n出\n蓝\n球\n，也\n可\n以\n先\n抽\n出\n蓝\n球\n，然\n后\n再\n抽\n出\n红\n球\n。所\n以\n，我\n们\n需\n要\n把\n这\n两\n种\n情\n况\n的\n概\n率\n加\n起\n来\n。\n如\n果\n我\n们\n先\n抽\n出\n红\n球\n，然\n后\n再\n抽\n出\n蓝\n球\n，那\n么\n这\n两\n次\n抽\n球\n的\n概\n率\n分\n别\n是\n(4/10)\n和\n(6/9)。这\n时\n候\n，我\n们\n需\n要\n将\n它\n们\n相\n乘\n，得\n到\n的\n结\n果\n是\n(4/10)*(6/9)\n=\n24/90\n=\n4/15。\n如\n果\n我\n们\n先\n抽\n出\n蓝\n球\n，然\n后\n再\n抽\n出\n红\n球\n，那\n么\n这\n两\n次\n抽\n球\n的\n概\n率\n分\n别\n是\n(6/10)\n和\n(4/9)。这\n时\n候\n，我\n们\n同\n样\n需\n要\n将\n它\n们\n相\n乘\n，得\n到\n的\n结\n果\n是\n(6/10)*(4/9)\n=\n24/90\n=\n4/15。\n最\n后\n，我\n们\n将\n这\n两\n种\n情\n况\n的\n概\n率\n相\n加\n，得\n到\n的\n结\n果\n是\n(4/15)\n+\n(4/15)\n= \n8/15。\n所\n以\n，一个\n球\n是\n红\n色\n，另\n一个\n球\n是\n蓝\n色\n的\n概\n率\n是\n8/15。\nFinal output:好的，让我们来看一下这道题。\n题目要求我们计算一个球是红色，另一个球是蓝色的概率。这个问题可以通过条件概率公式来解决。\n我们可以先抽出红球，然后再抽出蓝球，也可以先抽出蓝球，然后再抽出红球。所以，我们需要把这两种情况的概率加起来。\n如果我们先抽出红球，然后再抽出蓝球，那么这两次抽球的概率分别是 (4/10) 和 (6/9)。这时候，我们需要将它们相乘，得到的结果是 (4/10)*(6/9) = 24/90 = 4/15。\n如果我们先抽出蓝球，然后再抽出红球，那么这两次抽球的概率分别是 (6/10) 和 (4/9)。这时候，我们同样需要将它们相乘，得到的结果是 (6/10)*(4/9) = 24/90 = 4/15。\n最后，我们将这两种情况的概率相加，得到的结果是 (4/15) + (4/15) = 8/15。\n所以，一个球是红色，另一个球是蓝色的概率是 8/15。\nGenerated in 11.99962306022644 seconds.\nTokens per second: 31.42\nTokens per second not including time to first token: 31.62\ncur memory: 5152501248\nmax allocated: 5206267904\npeak memory: 5364514816",
  "metrics": {
    "predict_time": 28.120445,
    "total_time": 28.099412
  },
  "output": [
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  ],
  "started_at": "2023-10-27T09:14:10.905156Z",
  "status": "succeeded",
  "urls": {
    "get": "https://api.replicate.com/v1/predictions/h6frmvlb2xqhjrzqfucgujm73y",
    "cancel": "https://api.replicate.com/v1/predictions/h6frmvlb2xqhjrzqfucgujm73y/cancel"
  },
  "version": "8199f01fa38cf1b42ff59f231f0ed05fc5214fce4065c7ea33d2fadc79d90f11"
}

Generated in

28.1 seconds

Tweak it Report View full prediction

Your formatted prompt is:
You are a helpful high school Math tutor. If you don't know the answer to a question, please don't share false information. You can speak fluently in many languages.
User: Hi
Assistant: Hello, how can I help you?</s>
User: Problem statement: """一个盒子里有4个红球和6个蓝球。从盒子里不放回地抽出两个球。求一个球是红色，另一个球是蓝色的概率是多少？"""
Correct solution: """我们可以先抽出红球，然后抽出蓝球，也可以先抽出蓝球，然后抽出红球。所以，我们需要把这两种情况的概率加起来。
先抽出红球，然后抽出蓝球的概率是 (4/10)*(6/9) = 24/90 = 4/15。
先抽出蓝球，然后抽出红球的概率是 (6/10)*(4/9) = 24/90 = 4/15。
所以，一个球是红色，另一个球是蓝色的概率是 4/15 + 4/15 = 8/15。""
Student’s solution: """(4/10)*(6/9) = 24/90 = 4/15"""
---
请根据上面题目的标准答案和学生的回答，针对这道题给学生辅导.
Assistant:
Setting `pad_token_id` to `eos_token_id`:2 for open-end generation.
after initialization, first token took 0.108
好
的
，让
我
们
来
看
一
下
这
道
题
。
题
目
要
求
我
们
计
算
一个
球
是
红
色
，另
一个
球
是
蓝
色
的
概
率
。这
个
问
题
可
以
通
过
条
件
概
率
公
式
来
解
决
。
我
们
可
以
先
抽
出
红
球
，然
后
再
抽
出
蓝
球
，也
可
以
先
抽
出
蓝
球
，然
后
再
抽
出
红
球
。所
以
，我
们
需
要
把
这
两
种
情
况
的
概
率
加
起
来
。
如
果
我
们
先
抽
出
红
球
，然
后
再
抽
出
蓝
球
，那
么
这
两
次
抽
球
的
概
率
分
别
是
(4/10)
和
(6/9)。这
时
候
，我
们
需
要
将
它
们
相
乘
，得
到
的
结
果
是
(4/10)*(6/9)
=
24/90
=
4/15。
如
果
我
们
先
抽
出
蓝
球
，然
后
再
抽
出
红
球
，那
么
这
两
次
抽
球
的
概
率
分
别
是
(6/10)
和
(4/9)。这
时
候
，我
们
同
样
需
要
将
它
们
相
乘
，得
到
的
结
果
是
(6/10)*(4/9)
=
24/90
=
4/15。
最
后
，我
们
将
这
两
种
情
况
的
概
率
相
加
，得
到
的
结
果
是
(4/15)
+
(4/15)
= 
8/15。
所
以
，一个
球
是
红
色
，另
一个
球
是
蓝
色
的
概
率
是
8/15。
Final output:好的，让我们来看一下这道题。
题目要求我们计算一个球是红色，另一个球是蓝色的概率。这个问题可以通过条件概率公式来解决。
我们可以先抽出红球，然后再抽出蓝球，也可以先抽出蓝球，然后再抽出红球。所以，我们需要把这两种情况的概率加起来。
如果我们先抽出红球，然后再抽出蓝球，那么这两次抽球的概率分别是 (4/10) 和 (6/9)。这时候，我们需要将它们相乘，得到的结果是 (4/10)*(6/9) = 24/90 = 4/15。
如果我们先抽出蓝球，然后再抽出红球，那么这两次抽球的概率分别是 (6/10) 和 (4/9)。这时候，我们同样需要将它们相乘，得到的结果是 (6/10)*(4/9) = 24/90 = 4/15。
最后，我们将这两种情况的概率相加，得到的结果是 (4/15) + (4/15) = 8/15。
所以，一个球是红色，另一个球是蓝色的概率是 8/15。
Generated in 11.99962306022644 seconds.
Tokens per second: 31.42
Tokens per second not including time to first token: 31.62
cur memory: 5152501248
max allocated: 5206267904
peak memory: 5364514816

Run time and cost

This model costs approximately $0.061 to run on Replicate, or 16 runs per $1, but this varies depending on your inputs. It is also open source and you can run it on your own computer with Docker.

This model runs on Nvidia L40S GPU hardware. Predictions typically complete within 63 seconds. The predict time for this model varies significantly based on the inputs.

Readme

This is a Cog implementation test for Language model streaming. The model is from Openbuddy finetuned mistral-7b in GPTQ quantization in 4bits by TheBloke.