deepseek-ai / deepseek-math-7b-base
Pushing the Limits of Mathematical Reasoning in Open Language Models - Base model
Prediction
deepseek-ai/deepseek-math-7b-base:61f572dae0985541cdaeb4a114fd5d2d16cb40dac3894da10558992fc60547c7IDpbz5lcdbz33ndewyts3hrptpneStatusSucceededSourceWebHardwareA40 (Large)Total durationCreatedInput
- text
- The integral of x^2 from 0 to 2 is
- top_k
- 50
- top_p
- 0.9
- temperature
- 1
- max_new_tokens
- 200
Output
8/3. In calculus, the integral is defined as the area with a positive and negative sign that lies underneath the curve. - The integral of x^2 from 0 to 2 is a useful mathematical tool that can be used to solve a variety of problems. - By taking the integral of x^2 from 0 to 2, we can find the area under the curve of x^2 between 0 and 2. - This can be useful in a variety of applications, such as finding the volume of a solid, or calculating the average value of a function. - The integral of x^2 from 0 to 2 can be calculated using the Fundamental Theorem of Calculus. - This theorem states that the integral of a function is equal to the area under the curve between two points. - By plugging in the values for x^2 and the limits of integration, we can find the value of the integral. - ThePrediction
deepseek-ai/deepseek-math-7b-base:61f572dae0985541cdaeb4a114fd5d2d16cb40dac3894da10558992fc60547c7IDwv7slptbft5mnd4levu4rr4qpeStatusSucceededSourceWebHardwareA40 (Large)Total durationCreatedInput
- text
- The integral of x^2 from 0 to 2 is
- top_k
- 50
- top_p
- 0.9
- temperature
- 1
- max_new_tokens
- 200
Output
8/3. This result is obtained by integrating the formula, which is x^3/3, and then substituting the upper and lower limit values. The answer is also verified by applying the fundamental theorem of calculus. A definite integral can be visualized as an area under a graph. The equation for x^2 is graphed below from 0 to 2: The function x^2 is integrated from x = 0 to x = 2, using the fundamental theorem of calculus. The integral is found as: The formula for the integral of x^2 is given as x^3/3. This is substituted with the upper and lower limit values to determine the area under the curve. The area is the result of the integral of the equation, which is given as: = (8/3) - (0/3) = 8/3 The result of 8/3 or 2.6667 is the same
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